Write a function in C++ which accepts an integer array and its size as arguments / parameters and assign the elements into a two dimensional array of integers in the following format:

                                                                         CBSE 2006

If the array is 1 2 3 4 5 6

The resultant 2 D array is given below

1 2 3 4 5 6

1 2 3 4 5 0

1 2 3 4 0 0

1 2 3 0 0 0

1 2 0 0 0 0

1 0 0 0 0 0

If the array is 1 2 3

The resultant 2 D array is given below

1 2 3

1 2 0

1 0 0

#include<iostream.h>

#include<conio.h>

void form_matrix(int ar[], int m)

{

// forming the matrix 

int mat[m][m];

int max = m;

int min = 1;

for(int i = 0; i < m ; i++)

{

min= 1;

for(int j = 0; j < m ; j++, min++)

{

if(min < = max )

   mat[i][j] = min;

else

   mat[i][j] = 0;

}

max--;

}

cout<<" \n The matrix :";

// Displaying the matrix

for( i = 0 ; i < m; i++)

{

cout << "\n ";

for( j = 0 ; j< m ; j++)

cout << mat[i][j] << " ";

}

}

void main()

{

int m[10], sz, i, j;

cout<< " \n What is the size of an array ?";

cin >>  sz;

/* for inputing the  elements.....*/

for( i = 0 ; i < sz; i++)

m[i] = i+1;

cout << "\n The array ";

/* display array */

for( i = 0; i < sz ; i++)

cout<< m[i];

 /* call the function */

form_matrix(m, sz);

getch();

}

Write a function REASSIGN() in c++ , which accepts an array of integers and its size as parameters and divide all those array elements by 5 which are divisible by 5 and multiply other array elements by 2

CBSE 2010

#include<iostream.h>

#include<conio.h>

void REASSIGN(int a[], int size)

{

for(int i = 0 ; i < size ; i++)

{

if(a[i]%5 == 0)

  a[i] = a[i] / 5;

else 

   a[i] = a[i] * 2;

}

void main()

{

int arr[25];

int n, i;

cout << "\n Enter the size of an array (<25):":

cin >> n;

for( i = 0 ; i < n ; i++)

{cout<< "\n Enter an element :";

cin >> arr[i];

}

/* Display original array */

cout<< "\n The Original array :";

for(i = 0 ; i < n ; i++)

cout<< arr[i] << " ";

REASSIGN(arr, n);

cout<< "\n The changed array :";

/* Display the changed array */

for(i = 0 ; i < n ; i++)

cout<< arr[i] << " ";

getch();

}

Write a function int ALTERSUM( int B[][5] , int N, int M) in c++ to find and return the sum of elements from all alternate elements of a two-dimensional array starting from B[0][0].

Hint: If the following is the content of the array

4 5 1

2 8 7

9 6 3

The function should add elements B[0][0], B[0][2], B[1][1], B[2][0], B[2][2]

CBSE 2010

#include<iostream.h>

#include<conio.h>

#define x 10

#define y 5

int ALTERSUM(int B[][5], int M, int N)

{

int flag = 0, sum = 0;

for(int i = 0 ; i < M ; i++)

for(int j = 0 ; j < N ; j++)

{

if(flag == 0)

{ 

   sum = sum + B[i][j];

   flag = 1;

}

else

   flag = 0;

}

return sum;

}

void main()

{

int arr[x][y], r, c, i , j;

cout << "\n How many rows(<10)? " ;

cin >> r;

cout << "\n How many cols(< 5)?";

cin >> c;

/* Input elements */

for( i = 0 ; i < r ; i++)

for(j = 0 ; j< c ; j++)

{

cout << "\n Enter elements :";

cin >> arr[i][j];

}

/* display matrix */

for(i = 0; i < r  ; i++)

for(j = 0; j < c ; j ++)

    cout << arr[i][j] << " ";

cout<< endl;

int sum = ALTERSUM(arr, r, c);

cout << "\n The Sum of alternate elements = " << sum;

getch();

}

Write a function in C++ to print the product of each column of a two dimensional integer array passed as the argument of the function.

                                                    CBSE 2008

Explain : If the two dimensional array contains

         1     2     4

         3     5     6

         4     3     2

         2     1     5

The output should appear as :

Product of Column 1 = 24

Product of Column 2 = 30

Product of Column 3 = 240

                                                                                             

#include<iostream.h>

#include<conio.h>

#define r 10

# define c 10

void ProCol(int a[][], int m , int n) 

// n represents column

// m represents row

{

int pro[n], i, j ;

for(i = 0; i  <  n ; i++)

{

pro[i] = 1;

for(j = 0 ; j  <  m ; j ++)

{

pro[i] = pro[i] * a[j][i];

}

cout << "\n Product of Column 1 : " <<  pro[i];

}

}

void main()

{

int arr[r][c];

int row, col, i, j;

// Input dimension ~

cout <<  "\n Enter row & Column :";

cin >>  row >>  col ;

// Input elements for the array ~

for( i = 0; i <  row ; i++)

for ( j = 0 ; j <  col ; j++)

{

cout << "\n Enter the element for position : "   << i+1 << " , " <<  j+1 ;

cin >>  arr[i][j];

}

// Display the array

for( i = 0;  i < row ; i++ )

{

for( j =0 ; j < col ; j ++)

    cout   <<  arr[i][j]   <<  "  ";

cout  <<   endl;

}

// Calling the function

ProCol(arr, row, col);

getch();

}

Define a function SWAPCOL() in C++ to swap (interchange) the first column elements with the last column elements, for a two dimensional integer array passed as the argument of the function.

Example : If the two dimensional array contains 

       2   1   4   9

       1   3   7   7 

       5   8   6   3

       7   2   1   2

After swapping of the content of 1st column and the last column, it should be :

      9   1   4   2

      7   3   7   1

      3   8   6   5

      2   2   1   7                                (CBSE 2009)

#include<iostream.h>

#include<conio.h>

void swapcol(int a[][], int r, int c)
   // r -> row, c ->col

{ int t;

for(int i = 0; i< r ; i++)

{

t = a[i][0];

a[i][0] = a[i][c-1];

a[i][c-1] = t;

}

}

void main()

{

int arr[10][10];

int m, n, i, j;

cout<<"\n Enter rows & columns :";

int m, n;

cin >> m >> n;

/* Input Array Elements */

for ( i = 0; i< m ; i++)

for( j = 0; j < n ; j++)

{

cout<< "\n Enter element for the array[ " << i+1 << " ] "<< " [ " << j+i << "]" ;

cin >> arr[i][j];

}

/* Swap function call */

swapcol(arr, m, n);

/* Display Array in Matrix form */

for( i = 0; i < m ; << i ++)

{ cout<< endl;

for (  j = 0; j < n ; j ++)

cout << arr[i][j] << "  ";

}

getch();

}

Write a program to store 20 integers in an array. Then, accept another integer value and search for that integer in the array.

#include<iostream.h>

#include<conio.h>

#include <process.h>


void main()
{
int arr[20], i;


for( i= 0; i< 20 ; i++)
{cout<< "\n Enter an element :";
cin >> arr[i];
}


int x;


cout<<" \n Enter an element to be searched for :";
cin>> x;


for(i = 0; i< n ; i++)
{
if(x == arr[i])
{
cout<<" \n The element is found in position : " << i+1;
getch();
exit(1);
}
}


cout<< "\n The element not found ";
getch();
}

Write a program to enter the names and monthly salaries of 10 employees in a company. Now check individual per annum salary. If annual salary is greater than or equal to Rs 2,50000/- , then print name, salary and a message 'tax to be paid'; else print name, salary, and a message 'no tax'.

#include<iostream.h>

#include<conio.h>

void main()

{

char emp_nm[10], mon_sal[10];

/* ....Input .... */

for(int i = 0; i< 10; i++)

{

cout<<"\n enter the name of an employee :";

cin >> emp_nm[i];

cout<<"\n Enter the salary :";

cin>>mon_sal[i];

}

cout<< "Name" << "\t\t" << "Salary" << endl;

for(i = 0; i< 10; i++)

{

// Check annual salary ....

if(mon_sal[i]*12 >= 250000)

   cout<< emp_nm[i] << "\t\t"<< mon_sal[i] << "tax-to-be-paid"<< "\n" ;

else

   cout<< emp_nm[i] << "\t\t"<< mon_sal[i] << "no-tax"<< "\n" ;

}

getch();

}

Write a program to enter names; marks of 5 subjects for individual students for a class ( assume class can hold max. 30 students). Now, calculate total marks and print names , total in columnar format. (use 1D or 2D array )

#include<iostream.h>

#include<conio.h>

void main()

{

char name[30] ;

int marks[50][50], tot [ 50];

for ( int i = 0; i < 30 ; i++)

{

cout << "\n Enter Name of the student ";

cin >> name [i];

tot[i] = 0;

cout<< "\n Enter marks for 5 subjects : ";

for (int j = 0; j < 5 ; j++)

{ 

cout<< "\n Sub " << j+1;

cin >> marks[i][j];

tot[i] = tot[i] + marks[i][j];

}

}

clrscr(); 

cout<<"\n\n Name \t\t Total \n\n";

for( i = 0; i<=18 ; i ++)

{

cout<< name[i]  <<"\t\t" << tot[i] <<  "\n" ;

}

cout<<"\n Press any key to continue..... ";

getch();

clrscr();

cout<<"\n\n Name \t\t Total \n\n";

for( i = 19; i< 30 ; i ++)

{

cout<< name[i]  <<"\t\t" << tot[i]  <<  "\n" ;

}

 getch();

}