Write a function REASSIGN() in c++ , which accepts an array of integers and its size as parameters and divide all those array elements by 5 which are divisible by 5 and multiply other array elements by 2

CBSE 2010

#include<iostream.h>

#include<conio.h>

void REASSIGN(int a[], int size)

{

for(int i = 0 ; i < size ; i++)

{

if(a[i]%5 == 0)

  a[i] = a[i] / 5;

else 

   a[i] = a[i] * 2;

}

void main()

{

int arr[25];

int n, i;

cout << "\n Enter the size of an array (<25):":

cin >> n;

for( i = 0 ; i < n ; i++)

{cout<< "\n Enter an element :";

cin >> arr[i];

}

/* Display original array */

cout<< "\n The Original array :";

for(i = 0 ; i < n ; i++)

cout<< arr[i] << " ";

REASSIGN(arr, n);

cout<< "\n The changed array :";

/* Display the changed array */

for(i = 0 ; i < n ; i++)

cout<< arr[i] << " ";

getch();

}

Write a function int ALTERSUM( int B[][5] , int N, int M) in c++ to find and return the sum of elements from all alternate elements of a two-dimensional array starting from B[0][0].

Hint: If the following is the content of the array

4 5 1

2 8 7

9 6 3

The function should add elements B[0][0], B[0][2], B[1][1], B[2][0], B[2][2]

CBSE 2010

#include<iostream.h>

#include<conio.h>

#define x 10

#define y 5

int ALTERSUM(int B[][5], int M, int N)

{

int flag = 0, sum = 0;

for(int i = 0 ; i < M ; i++)

for(int j = 0 ; j < N ; j++)

{

if(flag == 0)

{ 

   sum = sum + B[i][j];

   flag = 1;

}

else

   flag = 0;

}

return sum;

}

void main()

{

int arr[x][y], r, c, i , j;

cout << "\n How many rows(<10)? " ;

cin >> r;

cout << "\n How many cols(< 5)?";

cin >> c;

/* Input elements */

for( i = 0 ; i < r ; i++)

for(j = 0 ; j< c ; j++)

{

cout << "\n Enter elements :";

cin >> arr[i][j];

}

/* display matrix */

for(i = 0; i < r  ; i++)

for(j = 0; j < c ; j ++)

    cout << arr[i][j] << " ";

cout<< endl;

int sum = ALTERSUM(arr, r, c);

cout << "\n The Sum of alternate elements = " << sum;

getch();

}