Write a c++ function that converts a 2 digit octal number into binary number and print the binary equivalent

This program converts any octal number to its binary equivalent

#include<iostream.h>

#include<conio.h>

#include<process.h>

#include<string.h>

void main()

{

char bina[30] = " ", temp[4] = " ", binar[30] = " ";

int oct;

int r;

cout << "\n Enter an octal number :";

cin >> oct;

int o = oct; // o is the backup of octal number

while(oct)

{

r = oct % 10;

oct = oct / 10;

switch(r)

{

case 1:

           strcpy(temp, "001");

           break;

case 2:

          strcpy(temp, "010");

          break;

case 3:

         strcpy(temp, "011");

         break;

case 4:

        strcpy(temp, "100");

        break;

case 5:

        strcpy(temp, "101");

        break;

case 6:

       strcpy(temp, "110");

       break;

case 7:

       strcpy(temp, "111");

       break;

default :

        cout << endl <<  o << "  is not an octal number ";

        getch();

        exit(1);

}

strcpy( binar, bina);

strcpy( bina, temp);

strcat( bina, binar );

}

cout << "\n The binary equivalent of  octal number " << o << " is " << bina ;

getch();

}