**eg. H.C.F of 11,22,33 is 11**

**L.C.M of 11,22,33 is 66**

**-------------------------------------**

**H.C.F of 2,3,4 is 1**

**L.C.M of 2,3,4 is 24**

**#include**

**<iostream.h>**

**#include**

**<conio.h>**

**void main()**

**{**

**int a, b, c; // three numbers**

**int hcf,lcm;**

**//calculate the minimum of three numbers**

**int min = (a < b ? a : b);**

**min = (min < c ? min : c);**

**for( int i = min; i>0; i--)**

**{**

**if(a%i == 0 && b%i == 0 && c%i == 0)**

**{**

**hcf = i;**

**break;**

**}**

**}**

**lcm = (a*b*c)/hcf;**

**cout<<" \n The H.C.F of " << a <<" , " << b << " , " << c << "is " << hcf;**

**cout<<" \n The L.C.M of " << a <<" , " << b << " , " << c << "is " << lcm;**

**getch();**

**}**

**/* Similarly you can calculate HCF of 2 numbers or 4 numbers and so on. */**

u shud hav to input 3 nos, otherwise the programming runs wrong.....

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